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Question: The co-ordinate axes are rotated through an angle 135<sup>0</sup>. If the co-ordinates of a point P ...

The co-ordinate axes are rotated through an angle 1350. If the co-ordinates of a point P in the new system are known to be (4, – 3), then the co-ordinates of P in the original system are-

A

(12,72)\left( \frac{1}{\sqrt{2}},\frac{7}{\sqrt{2}} \right)

B

(12,72)\left( \frac{1}{\sqrt{2}},–\frac{7}{\sqrt{2}} \right)

C

(12,72)\left( –\frac{1}{\sqrt{2}},–\frac{7}{\sqrt{2}} \right)

D

(12,72)\left( –\frac{1}{\sqrt{2}},\frac{7}{\sqrt{2}} \right)

Answer

(12,72)\left( \frac{1}{\sqrt{2}},–\frac{7}{\sqrt{2}} \right)

Explanation

Solution

q = 1350 (x1 , y1) ŗ (4 , – 3)

x = x1 cos q – y1 sin q ; y = x1 sin q + y1 cos q