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Question

Mathematics Question on binomial expansion formula

The co-efficient of x12x^{-12} in the expansion of(x+yx3)20\left(x+\frac{y}{x^3}\right)^{20}is

A

20C8\,^{20}C_8

B

20C8y8\,^{20}C_8y^8

C

20C12\,^{20}C_{12}

D

20C12y12\,^{20}C_{12}\,^y12

Answer

20C8y8\,^{20}C_8y^8

Explanation

Solution

Suppose x12x^{-12} occurs is (r + 1)th term. We have Tr+1=20Crx20r(yx3)rT_{r+1} = ^{20} C_{r} x^{20-r} \left(\frac{y}{x^{3}}\right)^{r} =20Crx204ryr = ^{20}C_{r} x^{20 -4r} y^{r} This term contains x12 x^{-12} if 204r=12 20-4r=-12 or r=8r = 8 . \therefore The coefficient of x12x^{-12} is 20C8y8{^{20}C_{8}} \, y^{8}