Solveeit Logo

Question

Question: The circumference of the base of a \(16m\) high solid cone is \(33m\) . Find the surface area of the...

The circumference of the base of a 16m16m high solid cone is 33m33m . Find the surface area of the cone.

Explanation

Solution

Cone is the solid figure with circular base and two sloping heights.
Here we are going to use formula for the surface area of the cone = πr(r+l)\pi r(r + l) and circumference of the circle= 2πr2\pi r

Complete step by step solution:
Given: Circumference of the circle = 33m33m
Height, h=16mh = 16m
Now, Circumference = 33m33m
2πr=332\pi r = 33
Putting value, π=227\pi = \frac{{22}}{7}
2×227×r=33\Rightarrow 2 \times \frac{{22}}{7} \times r = 33
Taking all the values on Right hand Side, making subject,
r=7×332×22 r=214 r=5.25m\begin{array}{l} r = \frac{{7 \times 33}}{{2 \times 22}}\\\ \Rightarrow r = \frac{{21}}{4}\\\ \Rightarrow r = 5.25m \end{array}
Now,
Slant height, l=h2+r2l = \sqrt {{h^2} + {r^2}}
Substituting values of h&rh\& r
l=162+(5.25)2 l=256+27.5625 l=283.5625 l=16.839 l=16.84m\begin{array}{l} l = \sqrt {{{16}^2} + {{(5.25)}^2}} \\\ l = \sqrt {256 + 27.5625} \\\ l = \sqrt {283.5625} \\\ l = 16.839\\\ l = 16.84m \end{array}
Total Surface area of cone= πr(r+l)\pi r(r + l)
Substituting all the values of r=5.25mr = 5.25m and l=16.84ml = 16.84m in the above equation
A=227×5.25(5.25+16.84) A=227×5.25(22.09) A=364.485m2\begin{array}{l} A = \frac{{22}}{7} \times 5.25(5.25 + 16.84)\\\ A = \frac{{22}}{7} \times 5.25(22.09)\\\ A = 364.485{m^2} \end{array}

Hence, the required answer is 364.485 meter square.

Additional Information: volume of the cone, V=13πr2hV = \frac{1}{3}\pi {r^2}h
Where r= radius of the circular base of the cone
h = height of the cone

Note: Always remember the standard basic formula for the solid figures and always double check the units given metre or centimetres and convert it accordingly. Units of all the given parameters should be the same