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Question: The circumference of a circle is measured as 56cm with an error 0.02cm. The percentage error in its ...

The circumference of a circle is measured as 56cm with an error 0.02cm. The percentage error in its area is
A. 17\dfrac{1}{7}
B. 128\dfrac{1}{28}
C. 114\dfrac{1}{14}
D. 156\dfrac{1}{56}

Explanation

Solution

Hint: We will use the derivative method to find the error percentage in the area. Also, we will use the formula of circumference of circle and area of the area which is given by.
Circumference=2πr Area=πr2 \begin{aligned} & Circumference=2\pi r \\\ & Area=\pi {{r}^{2}} \\\ \end{aligned}
Where ‘r’ is the radius of the circle.

Complete step-by-step answer:

We have been given the circumference of a circle as 56cm with an error of 0.02cm.
We know that circumference of a circle is equal to 2πr2\pi r, where ‘r’ is the radius of the circle.
Let us suppose the radius of the given circle is ‘r’ cm.
2πr=56 πr=28 r=28π \begin{aligned} & \Rightarrow 2\pi r=56 \\\ & \Rightarrow \pi r=28 \\\ & \Rightarrow r=\dfrac{28}{\pi } \\\ \end{aligned}
Circumference (C) =2πr=2\pi r
On differentiating both sides, we get
dcdr=2π.........(1)\dfrac{dc}{dr}=2\pi .........\left( 1 \right)
Now, we know that area of a circle is equal to πr2\pi {{r}^{2}}, where ‘r’ is the radius of the circle.
A=πr2\Rightarrow A=\pi {{r}^{2}}
On differentiating with respect of ‘r’ we get,
dAdr=d(πr2)dr\dfrac{dA}{dr}=\dfrac{d\left( \pi {{r}^{2}} \right)}{dr}
Since, π'\pi ' is a constant.
=πdr2dr=\pi \dfrac{d{{r}^{2}}}{dr}
As, we know that dxndx=n×xn1\dfrac{d{{x}^{n}}}{dx}=n\times {{x}^{n-1}}
dAdr=2πr.........(2)\Rightarrow \dfrac{dA}{dr}=2\pi r.........\left( 2 \right)
Now, dividing equation (2) by (1), we get,
dAdc=r dA=rdc \begin{aligned} & \dfrac{dA}{dc}=r \\\ & \Rightarrow dA=rdc \\\ \end{aligned}
Here, dA is the error in Area and dc is the error in circumference.
dA=r(0.02)\Rightarrow dA=r\left( 0.02 \right)
On dividing by πr2\pi {{r}^{2}} we get,
dAπr2=r(0.02)πr2 dAA=0.02πr \begin{aligned} & \dfrac{dA}{\pi {{r}^{2}}}=\dfrac{r\left( 0.02 \right)}{\pi {{r}^{2}}} \\\ & \dfrac{dA}{A}=\dfrac{0.02}{\pi r} \\\ \end{aligned}
We have πr=28\pi r=28.
dAA=0.0228 dAA=11400 \begin{aligned} & \Rightarrow \dfrac{dA}{A}=\dfrac{0.02}{28} \\\ & \Rightarrow \dfrac{dA}{A}=\dfrac{1}{1400} \\\ \end{aligned}
So, percentage error =dAA×100=11400×100=\dfrac{dA}{A}\times 100=\dfrac{1}{1400}\times 100
=114=\dfrac{1}{14}%
Therefore, the correct option of the given question is option (C).

Note: Remember that dA means the error in the function ‘A’ and on dividing it by A we get the relative error. Also, be careful while doing calculation and differentiation while finding the error and substitute the value carefully. Sometimes the student might miss the ‘2’ in the formula for circumference and this might lead to the wrong answer.