Question

The circuit shown in the figure contains two diodes each with a forward resistance of 50 $\Omega$ and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 $\Omega$ resistance (in ampere) is

• A. zero
• B. 0.02
• C. 0.03
• D. 0.036

Answer 1

Answer: (B)

0.02

Answer 2

The correct answer is B:0.02
In the circuit, diode $D_1$ in forward biased, while $D_2$ is reverse
biased. Therefore, current $i$ (through $D_1$ and 100 $\Omega$
resistance) will be
$i = \frac {6}{50 + 100 + 150} = 0.02A$
Here 50 $\Omega$ is the resistance of $D_1$ in forward biasing.