Question

The circuit shown in the figure contains two diodes each with a forward resistance of $30\Omega$ and with infinite backward resistance. If the battery is 3V, the current through the 50 $\Omega$ resistance (in ampere) is

• A. Zero
• B. $0.01$
• C. $0.02$
• D. $0.03$

Answer 1

Answer: (C)

$0.02$

Answer 2

: In the circuit the upper diode $D_{1}$is reverse biased and the lower diode $D_{2}$is forward biased. Thus there will be no current across upper diode junction. The effective circuit will be as shown in figure.

Total resistance of circuit

$R = 50 + 70 + 30 = 150\Omega$

Current in circuit, $I = \frac{V}{R} = \frac{3V}{150\Omega} = 0.02A$