Question
Question: The circuit shown here is used to compare the emf's of two cells E<sub>1</sub> and E<sub>2</sub> (E<...
The circuit shown here is used to compare the emf's of two cells E1 and E2 (E1> E2). The null point is at C when the galvanometer is connected to E1. When the galvanometer is connected to E2, the null point will be –
A
To the left of C
B
To the right of C
C
At C itself
D
No where on AB
Answer
To the left of C
Explanation
Solution
E1 = φ × l1 …(i)
it E2 < E1
E2 = φ × l2 …(ii)
l2 < l1
Hence balance point will shift towards left of C.