Question

The circuit has two oppositely connected ideal diodes in parallel. What is the current flowing in the circuit ?

• A. $1.71\, A$
• B. $2.00\, A$
• C. $2.31\, A$
• D. $1.33\, A$

Answer 1

Answer: (B)

$2.00\, A$

Answer 2

In the given circuit diode D, is reverse biased while $D_2$ is forward biased, so the circuit can be redrawn as: [$\because$ For ideal diodes, reverse biased means open and forward biased means short] Apply $KVL$ to get current flowing through the circuit $-12+4i+2i=0 \Rightarrow i=\frac{12}{6}=2A$