Question

The circuit given in figure, is equivalent to

• A. AND gate
• B. OR gate
• C. NOT gate
• D. NAND gate

Answer 1

Answer: (A)

AND gate

Answer 2

: The output of circuit

$Y = \overline{\bar{A} + \bar{B}} = \bar{\bar{A}}.\bar{\bar{B}} = AB$

Therefore, output is equivalent to AND gate.