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Question: The circle x<sup>2</sup> + y<sup>2</sup> – 6x – 10y + p = 0 does not touch nor intersect the coordin...

The circle x2 + y2 – 6x – 10y + p = 0 does not touch nor intersect the coordinate axes if the point (1, 4) lies inside the circle then –

A

0 < p < 29

B

25 < p < 29

C

25 < p < 35

D

None of these

Answer

25 < p < 29

Explanation

Solution

S = x2 + y2 – 6x – 10y + p = 0

P(1, 4)

g2 – c < 0 ̃ 9 – p < 0 ̃ p – 9 > 0 ...(i)

f2 – c < 0 ̃ 25 – p < 0 ̃ p – 25 > 0 ...(ii)

S1 < 0

1 + 16 – 6 – 40 + p < 0 ̃ p – 29 < 0

p < 29 ...(iii)

comparing (i), (ii) & (iii)

25 < p < 29