Question
Question: The circle \(x ^ { 2 } + y ^ { 2 } - 3 x - 4 y + 2 = 0\) cuts x-axis at....
The circle x2+y2−3x−4y+2=0 cuts x-axis at.
A
(2,0),(−3,0)
B
(3,0),(4,0)
C
(1,0),(−1,0)
D
(1,0),(2,0)
Answer
(1,0),(2,0)
Explanation
Solution
Given, equation of circle is x2+y2−3x−4y+2=0 and it cuts the x-axis.
∴ x2+0−3x+2=0 or x2−3x+2=0 or (x−1)(x−2)=0 or Therefore the points are (1,0) and (2, 0).