Solveeit Logo

Question

Question: The circle \(x ^ { 2 } + y ^ { 2 } - 3 x - 4 y + 2 = 0\) cuts x-axis at....

The circle x2+y23x4y+2=0x ^ { 2 } + y ^ { 2 } - 3 x - 4 y + 2 = 0 cuts x-axis at.

A

(2,0),(3,0)( 2,0 ) , ( - 3,0 )

B

(3,0),(4,0)( 3,0 ) , ( 4,0 )

C

(1,0),(1,0)( 1,0 ) , ( - 1,0 )

D

(1,0),(2,0)( 1,0 ) , ( 2,0 )

Answer

(1,0),(2,0)( 1,0 ) , ( 2,0 )

Explanation

Solution

Given, equation of circle is x2+y23x4y+2=0x ^ { 2 } + y ^ { 2 } - 3 x - 4 y + 2 = 0 and it cuts the x-axis.

\therefore x2+03x+2=0x ^ { 2 } + 0 - 3 x + 2 = 0 or x23x+2=0x ^ { 2 } - 3 x + 2 = 0 or (x1)(x2)=0( x - 1 ) ( x - 2 ) = 0 or Therefore the points are (1,0) and (2, 0).