Question
Chemistry Question on Structural Representations Of Organic Compounds
The chirality of the compound
R
S
Z
E
R
Solution
We need to know that the "right hand" and "left hand" classifications can be utilized to name the enantiomers of a chiral compound. In that event, the bolt is focused in a counterclockwise way, and the design of the stereo-center is visible as S.
We also need to know that, at the alphabet E, the level of strokes are largely on a similar side; in the E isomer, the higher need more bunches which are present on the inverse sides. In the Z shape, the even strokes are on opposite sides; in the Z isomer, the gatherings are on similar sides.
The less needed molecule is in every case away from the watcher. The need is seen based on nuclear numbers furthermore if nuclear numbers are the same based on nuclear mass. Find in the request for higher to bring down need.
The stereochemistry structure of the compound is given,
On the off chance, that will be clockwise, this is R.
On the off chance, that will be in anticlockwise, this is S.
So, The complete name of that particle is (R) 1 - bromo-1 - chloroethane.
Hence, the correct option is (A).