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Question

Water Resources Engineering Question on Darcy’s Law and application

The chezy's coefficient 'C' is related to Darcy-Weisbach friction factor 'f' as -

A

C=(8g/f14)C=\sqrt{(8g/f^{\frac{1}{4}})}

B

C=(8g/f)C=\sqrt{(8g/f)}

C

C=(g/8f)C=\sqrt{(g/8f)}

D

C=(f/8g)C=\sqrt{(f/8g)}

Answer

C=(8g/f)C=\sqrt{(8g/f)}

Explanation

Solution

The correct answer is (B) : C=(8g/f)C=\sqrt{(8g/f)}.