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Question: The charges on two sphere are +7μC and – 5μC respectively. They experience a force F. If each of the...

The charges on two sphere are +7μC and – 5μC respectively. They experience a force F. If each of them is given and additional charge of – 2μC, the new force of attraction will be

A

F

B

F / 2

C

F/3F/\sqrt{3}

D

2F

Answer

F

Explanation

Solution

F=14πε0(+7×10−6)(−5×10−6)r2=−14πε035×1012r2NF = \frac{1}{4\pi\varepsilon_{0}}\frac{( + 7 \times 10^{- 6})( - 5 \times 10^{- 6})}{r^{2}} = - \frac{1}{4\pi\varepsilon_{0}}\frac{35 \times 10^{12}}{r^{2}}N

F′=14πε0(+5×10−6)(−7×10−6)r2=−14πε035×1012r2NF' = \frac{1}{4\pi\varepsilon_{0}}\frac{( + 5 \times 10^{- 6})( - 7 \times 10^{- 6})}{r^{2}} = - \frac{1}{4\pi\varepsilon_{0}}\frac{35 \times 10^{12}}{r^{2}}N