Question

The charge required for the reduction of $1$ mol of $MnO_4^-$ to $MnO_2$ is

• A. 1 F
• B. 3 F
• C. 5 F
• D. 6 F

Answer 1

Answer: (B)

3 F

Answer 2

$MnO _{4}^{-}+2 H _{2} O +3 e ^{-} \longrightarrow MnO _{2}+4 OH ^{-}$
In the above reduction requires flow of $3$ moles of electrons. So it required $3 F$ charge.