Question

The charge Q is placed at each of the two opposite corners of a square. A charge q is placed at each of the other two opposite corners. If charges q are fixed, then for equilibrium of Q, it is required that-

• A. q = $\frac{Q}{2\sqrt{2}}$
• B. q = –$\frac{Q}{2\sqrt{2}}$
• C. q = –$\frac{Q}{4}$
• D. q = –2$\sqrt{2}$Q

Answer 1

Answer: (C)

q = –$\frac{Q}{4}$

Answer 2

F =

F ' =

F ' =