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Question: The charge on a particle Y is double the charge on particle X. These two particles X and Y after bei...

The charge on a particle Y is double the charge on particle X. These two particles X and Y after being accelerated through the same potential difference enter a region of uniform magnetic field and describe circular paths of radii R1R _ { 1 } and R2R _ { 2 } respectively. The ratio of the mass of X to that of Y is

A

(2R1R2)2\left( \frac { 2 R _ { 1 } } { R _ { 2 } } \right) ^ { 2 }

B

(R12R2)2\left( \frac { R _ { 1 } } { 2 R _ { 2 } } \right) ^ { 2 }

C

R122R22\frac { R _ { 1 } ^ { 2 } } { 2 R _ { 2 } ^ { 2 } }

D

2R1R2\frac { 2 R _ { 1 } } { R _ { 2 } }

Answer

R122R22\frac { R _ { 1 } ^ { 2 } } { 2 R _ { 2 } ^ { 2 } }

Explanation

Solution

r=1B2mVqrmqrxry=mxqx×qymyr = \frac { 1 } { B } \sqrt { \frac { 2 m V } { q } } \Rightarrow r \propto \sqrt { \frac { m } { q } } \Rightarrow \frac { r _ { x } } { r _ { y } } = \sqrt { \frac { m _ { x } } { q _ { x } } \times \frac { q _ { y } } { m _ { y } } }

R1R2=mxmy×21mxmy=R122R22\Rightarrow \frac { R _ { 1 } } { R _ { 2 } } = \sqrt { \frac { m _ { x } } { m _ { y } } \times \frac { 2 } { 1 } } \Rightarrow \frac { m _ { x } } { m _ { y } } = \frac { R _ { 1 } ^ { 2 } } { 2 R _ { 2 } ^ { 2 } }