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Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

The charge on 11 gram ions of Al3+Al^{3+} is

A

127NAe\frac{1}{27} N_{A}e coulomb

B

13×NAe\frac{1}{3} \times N_{A}e coulomb

C

19×NAe\frac{1}{9} \times N_{A}e coulomb

D

3×NAe3 \times N_{A}e coulomb

Answer

19×NAe\frac{1}{9} \times N_{A}e coulomb

Explanation

Solution

11 gram ion =1= 1 mole So, charge on 11 mole Al3+Al^{3+} is 3×NAe3 \times N_{A}e