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Question: The change of momentum in each ball of mass \(60gm\), moving in opposite directions with speeds \(4m...

The change of momentum in each ball of mass 60gm60gm, moving in opposite directions with speeds 4m/s4m/s collide and rebound with the same speed, is The change of momentum in each ball of mass 60gm60gm, moving in opposite directions with speeds 4m/s4m/s collide and rebound with the same speed, is

The change of momentum in each ball of mass 60gm60gm, moving in opposite directions with speeds 4m/s4m/s collide and rebound with the same speed, is

A

0.98kgm/s0.98kg ⥂ - ⥂ m/s

B

0.73kgm/s0.73kg ⥂ - ⥂ m/s

C

0.48kgm/s0.48kg ⥂ - ⥂ m/s

D

0.22kgm/s0.22kg ⥂ - ⥂ m/s

Answer

0.48kgm/s0.48kg ⥂ - ⥂ m/s

Explanation

Solution

Momentum before collision = mv, Momentum after

collision = – mv

∴ Change in momentum

=2mv=2×60×103×4=480×103kgm/s=0.48kgm/s= 2mv = 2 \times 60 \times 10^{- 3} \times 4 = 480 \times 10^{- 3}kg ⥂ - ⥂ m ⥂ / ⥂ s = 0.48kg - ⥂ m ⥂ / ⥂ s