Solveeit Logo
Login

Question

Question: The CFSE for octahedral \(\lbrack CoCl_{6}\rbrack^{4 -}\)is 18,000 \(cm^{- 1}\). The CFSE for tetrah...

The CFSE for octahedral [CoCl6]4−\lbrack CoCl_{6}\rbrack^{4 -}is 18,000 cm−1cm^{- 1}. The CFSE for tetrahedral [CoCl4]2−\lbrack CoCl_{4}\rbrack^{2 -}will be

A

18,000cm−118,000cm^{- 1}

B

16,000cm−116,000cm^{- 1}

C

8,000cm−18,000cm^{- 1}

D

20,000cm−120,000cm^{- 1}

Answer

8,000cm−18,000cm^{- 1}

Explanation

Solution

Δt=4/9Δ0=(4/9)(18,000cm−1)=8000cm−1\Delta_{t} = 4/9\Delta_{0} = (4/9)(18,000cm^{- 1}) = 8000cm^{- 1}