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Question: The centroid of a triangle, whose vertices are (2,1), (5,2) and (3,4), is....

The centroid of a triangle, whose vertices are (2,1), (5,2) and (3,4), is.

A

(83,73)\left( \frac{8}{3},\frac{7}{3} \right)

B

(103,73)\left( \frac{10}{3},\frac{7}{3} \right)

C

(103,73)\left( - \frac{10}{3},\frac{7}{3} \right)

D

(103,73)\left( \frac{10}{3}, - \frac{7}{3} \right)

Answer

(103,73)\left( \frac{10}{3},\frac{7}{3} \right)

Explanation

Solution

x=2+5+33=103x = \frac { 2 + 5 + 3 } { 3 } = \frac { 10 } { 3 } and y=1+2+43=73y = \frac { 1 + 2 + 4 } { 3 } = \frac { 7 } { 3 }.