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Question: The centre of sphere passes through four points (0, 0, 0), (0, 2, 0), (1, 0, 0) and (0, 0, 4) is s...

The centre of sphere passes through four points (0, 0, 0),

(0, 2, 0), (1, 0, 0) and (0, 0, 4) is

s

A

(12,1,2)\left( \frac{1}{2},1,2 \right)

B

(12,1,2)\left( - \frac{1}{2},1,2 \right)

C

(12,1,2)\left( \frac{1}{2},1, - 2 \right)

D

(1,12,2)\left( 1,\frac{1}{2},2 \right)

Answer

(12,1,2)\left( \frac{1}{2},1,2 \right)

Explanation

Solution

Let the equation of sphere

x2+y2+z2+2ux+2vy+2wz+d=0x ^ { 2 } + y ^ { 2 } + z ^ { 2 } + 2 u x + 2 v y + 2 w z + d = 0

\bullet \bullet It passes through origin (0, 0, 0),

d=0d = 0

Also, it passes through (0, 2, 0)

4+4v=0v=14 + 4 v = 0 \Rightarrow v = - 1

Also, it passes through (1, 0, 0)

1+2u=0u=1/21 + 2 u = 0 \Rightarrow u = - 1 / 2

And it passes through (0, 0, 4)

16+8ww=216 + 8 w \Rightarrow w = - 2

∴ Centre (u,v,w)=(12,1,2)( - u , - v , - w ) = \left( \frac { 1 } { 2 } , 1,2 \right).