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Question: The centre of mass of a system of two particles of masses m1 and m2 is at a distance dl from \(m_{1}...

The centre of mass of a system of two particles of masses m1 and m2 is at a distance dl from m1m_{1} and at a distance d2 from mass m2 such that

A

d1d2=m2m1\frac{d_{1}}{d_{2}} = \frac{m_{2}}{m_{1}}

B

d1d2=m1m2\frac{d_{1}}{d_{2}} = \frac{m_{1}}{m_{2}}

C

d1d2=m1m1+m2\frac{d_{1}}{d_{2}} = \frac{m_{1}}{m_{1} + m_{2}}

D

d1d2=m2m1+m2\frac{d_{1}}{d_{2}} = \frac{m_{2}}{m_{1} + m_{2}}

Answer

d1d2=m2m1\frac{d_{1}}{d_{2}} = \frac{m_{2}}{m_{1}}

Explanation

Solution

Refer figure.

The distances of centre of mass CM form masses m1m_{1}and m2m_{2}are

d1=m2dm1+m2andd2=m1dm1+m2d1d2=m2m1d_{1} = \frac{m_{2}d}{m_{1} + m_{2}}andd_{2} = \frac{m_{1}d}{m_{1} + m_{2}} \therefore\frac{d_{1}}{d_{2}} = \frac{m_{2}}{m_{1}}