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Question

Physics Question on System of Particles & Rotational Motion

The centre of mass of a system of two bodies of masses MM and m,(M>m)1m, (M > m)1 separated by a distance dd is

A

midway between the bodies

B

closer to the heavier body

C

closer to the lighter body

D

at the centre of the heavier body

Answer

closer to the heavier body

Explanation

Solution

Let x1x_1 and x2x_2 be distances of centre of mass from the two bodies of masses MM and m(M>m)m (M > m) respectively.
As Mx1=mx2x1x2=mMMx_1 = mx_2 \:\:\:\:\: \therefore \:\: \frac{x_1}{x_2} = \frac{m}{M}
M>m\because \:\: M > m or m<Mm < M
x1x2<1\therefore \:\:\:\: \frac{x_1}{x_2} < 1 or x1<x2x_1 < x_2
Thus, the centre of mass is closer to the heavier body.