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Question

Question: The cell \(\text{Zn }|\text{ Z}\text{n}^{\text{2+}}(\text{1M})\ ||\text{ C}\text{u}^{\text{2+}}(\te...

The cell

Zn  Zn2+(1M)  Cu2+(1M)  Cu : (E0cell = 1.10V) \text{Zn }|\text{ Z}\text{n}^{\text{2+}}(\text{1M})\ ||\text{ C}\text{u}^{\text{2+}}(\text{1M})\ |\text{ Cu : }({E^{0}}_{\text{cell}}\text{ = 1.10V})\ was allowed to completely discharge at 298 K. The relative concentration of Zn2+ to Cu2+([Zn2+][Cu2+])\text{Z}\text{n}^{\text{2+}}\text{ to C}\text{u}^{\text{2+}}\left( \frac{\left\lbrack Zn^{2 +} \right\rbrack}{\left\lbrack Cu^{2 +} \right\rbrack} \right) is :

(Take1.10.059\frac{1.1}{0.059}= 18.65)

A

1037.3

B

9.65 × 104

C

Antilog (24.08)

D

37.3

Answer

1037.3

Explanation

Solution

0 = + 1.1 - 0.05912log[Zn2+][Cu2+] ;log [Zn2+][Cu2+] = 37.3.; [Zn2+][Cu2+] = 1037.3\text{0 = + 1.1 - }\frac{\text{0.0591}}{2}\text{log}\frac{\left\lbrack \text{Z}\text{n}^{2 +} \right\rbrack}{\left\lbrack Cu^{2 +} \right\rbrack}\text{ ;log }\frac{\left\lbrack \text{Z}\text{n}^{2 +} \right\rbrack}{\left\lbrack Cu^{2 +} \right\rbrack}\text{ = 37.3.; }\frac{\left\lbrack \text{Z}\text{n}^{2 +} \right\rbrack}{\left\lbrack Cu^{2 +} \right\rbrack}\text{ = 1}\text{0}^{\text{37.3}}