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Physics Question on Ray optics and optical instruments

The Cauchy's dispersion formula is

A

n=A+Bλ−2+Cλ−4n=A+B\lambda^{-2}+C\lambda^{-4}

B

n=A+Bλ−2+Cλ4n=A+B\lambda^{-2}+C\lambda^{4}

C

n=A+Bλ2+Cλ−4n=A+B\lambda^{2}+C\lambda^{-4}

D

n=A+Bλ2+Cλ4n=A+B\lambda^{2}+C\lambda^{4}

Answer

n=A+Bλ−2+Cλ−4n=A+B\lambda^{-2}+C\lambda^{-4}

Explanation

Solution

The Cauchy's dispersion formula represents the dispersion of most of the substances with considerable accuracy. Also from the Cauchy's dispersion formula if nn is refractive index and A,BA, B and CC are constants, then
n=A+Bλ−2+Cλ−4n = A + B \lambda^{-2} + C\lambda^{-4}

So, the correct option is (A): n=A+Bλ−2+Cλ−4n = A + B \lambda^{-2} + C\lambda^{-4}