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Question

Chemistry Question on Galvanic Cells

The cathode reaction in the dry cell will be

A

\ceZn(s)−>Zn2++2e−\ce{ Zn_{(s)} -> Zn^{2+} + 2e^- }

B

\ceMnO2+NH4++e−−>MnO(OH)+NH3\ce{ MnO_2 + NH^+_4 + e^- -> MnO(OH) + NH_3}

C

\ceZn(Hg)+2OH−−>ZnO(s)+H2O+2e−\ce{ Zn(Hg) + 2OH^- -> ZnO_{(s)} + H_2O + 2e^-}

D

\ceMnO(OH)+NH3−−>MnO2+NH4++2e−\ce{MnO(OH) + NH_3 - -> MnO_2 + NH^+_4 + 2e^- }

Answer

\ceMnO2+NH4++e−−>MnO(OH)+NH3\ce{ MnO_2 + NH^+_4 + e^- -> MnO(OH) + NH_3}

Explanation

Solution

Answer (b) MnO2+NH4++e−−>MnO(OH)+NH3 { MnO_2 + NH^+_4 + e^- -> MnO(OH) + NH_3}