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Question

Mathematics Question on Three Dimensional Geometry

The Cartesian equation of the line passing through (7, 5, 3) and perpendicular to the plane 3x + 2y + z = 6 is

A

x−73=y−52=z−31\frac{x-7}{3}=\frac{y-5}{2}=\frac{z-3}{1}

B

x−37=y−25=z−13\frac{x-3}{7}=\frac{y-2}{5}=\frac{z-1}{3}

C

x−37=y−25=z3\frac{x-3}{7}=\frac{y-2}{5}=\frac{z}{3}

D

x−73=y−51=z−32\frac{x-7}{3}=\frac{y-5}{1}=\frac{z-3}{2}

E

x−44=y−33=z−22\frac{x-4}{4}=\frac{y-3}{3}=\frac{z-2}{2}

Answer

x−73=y−52=z−31\frac{x-7}{3}=\frac{y-5}{2}=\frac{z-3}{1}

Explanation

Solution

The correct option is (A): x−73=y−52=z−31\frac{x-7}{3}=\frac{y-5}{2}=\frac{z-3}{1}