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Question

Physics Question on communication systems

The carrier frequency of a transmitter is provided by a tank circuit of a coil of inductance 49μH 49\,\mu H and a capacitance of 2.5nF2.5 \,nF. It is modulated by an audio signal of 12kHz12 \,kHz. The frequency range occupied by the side bands is:

A

13482 kHz - 13494 kHz

B

442 kHz - 466 kHz

C

63 kHz - 75 kHz

D

18 kHz - 30 kHz

Answer

442 kHz - 466 kHz

Explanation

Solution

The tank circuit of an inductance and a capacitance is know that ω=1LC=149μH×2.5nF=149×106×2.5×109\omega=\frac{1}{\sqrt{L C}}=\frac{1}{\sqrt{49 \mu H \times 2.5\, nF }}=\frac{1}{\sqrt{49 \times 10^{-6} \times 2.5 \times 10^{-9}}} ω=149×25×1016=17×5×108\Rightarrow \omega=\frac{1}{\sqrt{49 \times 25 \times 10^{-16}}}=\frac{1}{7 \times 5 \times 10^{-8}} ω=2πff=ω2π=17×5×108×2πf=454.5kHz\omega=2 \pi f \Rightarrow f=\frac{\omega}{2 \pi}=\frac{1}{7 \times 5 \times 10^{-8} \times 2 \pi} \Rightarrow f=454.5\, kHz Given carrier frequency is modulated by audio signal of 12kHz12 \,kHz. Therefore, f=454.5kHz±12kHzf=454.5\, kHz \pm 12 \,kHz f=442kHz466kHz \Rightarrow f=442 \,kHz -466\, kHz