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Question

Physics Question on Combination of capacitors

The capacitors of capacitance 4μF4\,\mu F and 6μF6\,\mu F are connected in series. A potential difference of 500volt500\, volt is applied to the outer plates of capacitor system. Then the charge on each capacitor is equal to

A

600 coulomb

B

1200 coulomb

C

1200 micro coulomb

D

600 micro coulomb.

Answer

1200 micro coulomb

Explanation

Solution

Total capacitance, Cs=4×64+6μC_s = \frac{4 \times 6}{4 + 6} \, \mu F = 2.4 μ\muF Charge q=VCs=500×2.4×106q = VC_s = 500 \times 2.4 \times 10^6 = 1200 μ\muC