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Question: The capacitor of capacitance \(4\mu F\)and \(6\mu F\)are connected in series. A potential difference...

The capacitor of capacitance 4μF4\mu Fand 6μF6\mu Fare connected in series. A potential difference of 500 6muvolts500\mspace{6mu} volts applied to the outer plates of the two capacitor system. Then the charge on each capacitor is numerically

A

6000C6000C

B

1200 6muC1200\mspace{6mu} C

C

1200 6muμC1200\mspace{6mu}\mu C

D

6000 6muμC6000\mspace{6mu}\mu C

Answer

1200 6muμC1200\mspace{6mu}\mu C

Explanation

Solution

Ceq=C1C2C1+C2=2.4μF.C_{eq} = \frac{C_{1}C_{2}}{C_{1} + C_{2}} = 2.4\mu F.

Charge flown = 2.4 × 500 × 10–6 C

=1200 μC.