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Question: The capacitor of capacitance \(4\mu F\) and\(6\mu F\) are connected in series. A potential differenc...

The capacitor of capacitance 4μF4\mu F and6μF6\mu F are connected in series. A potential difference of 5006muvolts500\mspace{6mu} volts is applied to the outer plates of the two capacitor system. The potential difference across the plates of capacitor of 4μF4\mu F capacitance is

A

5006muvolts500\mspace{6mu} volts

B

3006muvolts300\mspace{6mu} volts

C

2006muvolts200\mspace{6mu} volts

D

2506muvolts250\mspace{6mu} volts

Answer

3006muvolts300\mspace{6mu} volts

Explanation

Solution

Potential difference across 4μF capacitor

V=(64+6)×500=300voltV = \left( \frac{6}{4 + 6} \right) \times 500 = 300volt