Question

The capacities and connection of five capacitors are shown in the adjoining figure. The potential difference between the points $A$ and $B$ is $60\mspace{6mu} volts$. Then the equivalent capacity between $A$ and $B$ and the charge on $5\mu F$ capacitance will be respectively

• A. (a) $44\mu F;\mspace{6mu} 300\mu C$
• A. (b) $16\mu F;\mspace{6mu} 150\mu C$
• A. (c) $15\mu F;\mspace{6mu} 200\mu C$
• A. (d) $4\mu F;\mspace{6mu} 50\mu C$

Answer 1

(d)

Sol. The given circuit can be redrawn ass follows

Equivalent capacitance of the circuit

$C_{AB} = 4\mu F$

Charge given by the battery

$Q = C_{eq}V = 4 \times 60 = 240\mu C$

Charge in 5μF capacitor

$Q' = \frac{5}{(10 + 5 + 9)} \times 240 = 50\mu C$