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Physics Question on Calculating the Capacitance

The capacitance of a parallel plate capacitor becomes 43\frac{4}{3} times its original value if a dielectric slab of thickness t=d2\frac{d}{2} is inserted between the plates (where d is the distance of separation between the plates). What is the dielectric constant of the slab?

A

K=2

B

K=12K=\frac{1}{2}

C

K=1

D

K=2K=\sqrt2

Answer

K=2

Explanation

Solution

The correct option is (A) : K=2