Question
Physics Question on Wave optics
The Brewsters angle ib for an interface should be:
A
0<ib<30
B
30<ib<45
C
45<ib<90
D
ib=90
Answer
45<ib<90
Explanation
Solution
Brewster's angle is the angle at which light with a specific polarization passes through a dielectric surface without any reflection. When unpolarized light hits the surface at this angle, the reflected light is completely polarized.
Calculation:
At the interface, Brewster's angle ib is given by: μ=tanib (1)
Here, μ is the refractive index of the material, which ranges from 1 to ∞: 1<μ<∞
Substituting equation (1) into this range, we get: 1<tanib<∞
Therefore, the polarization angle ib falls within: tan−1(1)<ib<tan−1(∞)
⇒45∘<ib<90∘