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Question

Physics Question on Wave optics

The Brewsters angle ibi_b for an interface should be:

A

0<ib<300< i b < 30

B

30<ib<4530< i_b < 45

C

45<ib<9045< i_b < 90

D

ib=90i_b = 90

Answer

45<ib<9045< i_b < 90

Explanation

Solution

Brewster's angle is the angle at which light with a specific polarization passes through a dielectric surface without any reflection. When unpolarized light hits the surface at this angle, the reflected light is completely polarized.

Calculation:

At the interface, Brewster's angle ibi_b​ is given by: μ=tanib (1)μ=tan⁡i_b \ (1)

Here, μ\mu is the refractive index of the material, which ranges from 1 to ∞: 1<μ<1 < \mu < \infty

Substituting equation (1) into this range, we get: 1<tanib<1 < \tan i_b < \infty

Therefore, the polarization angle ib i_b falls within: tan1(1)<ib<tan1()\tan^{-1}(1) < i_b < \tan^{-1}(\infty)
45<ib<90\Rightarrow 45^\circ < i_b < 90^\circ