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Question

Physics Question on Polarisation

The Brewster's law is given by the expression

A

μ=sin⁡ isin⁡ r\mu =\frac{\sin \,i}{\sin \,r}

B

μ=tan⁡ θ0\mu =\tan \,\theta^{0}

C

μ=cos⁡θ \mu =\cos \theta

D

μ=sin⁡θ \mu =\sin\theta

Answer

μ=tan⁡ θ0\mu =\tan \,\theta^{0}

Explanation

Solution

From Brewster's law μ=tan⁡ θP \mu =\tan \,\theta_{P}