Question
Chemistry Question on Chemical bonding and molecular structure
The bond order of O2+,O2,O22− and O2− varies in the order:
O2+>O2>O22−>O2−
O22−>O2−>O2>O2+
O2+>O2>O2−>O22−
O2>O2+>O2−>O22−
O2+>O2>O2−>O22−
Solution
Electronic configuration of O2+: σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2px2,π2py2 =π2pz2,π∗2py1=π∗2pz0 ∴ bond order of σ2+=21 (bonding electron - antibonding electron) =21(10−5) =21×5=2.5 Electronic configuration of O2+: σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2px2,π2py2 =π2px2,π∗2py1=π∗2pz1 ∴ bond order of O2=21(10−6) =21×4=2 Electronic configuration of O22−: σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2px2,π2py2 π2pz2,π∗2py2=π∗2pz2 ∴ bond order of O22−=21(10−8) =21×2=1 Electronic configuration of O2−: σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2px2,π2py2 =π2pz2,π∗2py2=π∗2pz1 ∴ bond order of O2−=21(10−7) =21×3=1.5 Hence, the bond order of O2+,O2,O22− and O2− varies in the order : O2+>O2>O2−>O22−