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Question

Chemistry Question on Molecular Orbital Theory

The bond order of COCO molecule is

A

2

B

2.5

C

3

D

3.5

Answer

3

Explanation

Solution

CO(6+8=14)σ(1s)2,σ∗(1s)2,σ(2s)2,σ∗(2s)2,π(2px)2≈π(2py)2,σ(2pz)2CO (6+8=14) \sigma(1 s)^{2}, \sigma^{*}(1 s)^{2}, \sigma(2 s)^{2},\sigma^{*}(2 s)^{2}, \pi\left(2 p_{x}\right)^{2} \approx \pi\left(2 p_{y}\right)^{2}, \sigma\left(2 p_{z}\right)^{2} B⋅O=Nb−Na2B \cdot O =\frac{N_{b}-N_{a}}{2} =10−42=3=\frac{10-4}{2}=3