Question

The bond order of $C_2$ molecule is

• A. 1
• B. 2
• C. 0
• D. 3

Answer 1

Answer: (B)

2

Answer 2

The correct option is(B): 2.

The electronic configuration of $C _{2}$ molecule is as
$C _{2}=\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, \pi 2 p_{y}^{2}=\pi 2 p_{z}^{2}$
Bond order $= \frac{N_b - N_a}{2}$
$=\frac{8-4}{2}$
$=2$