Question
Question: The bond dissociation energies of gaseous \({{H}_{2}}\), \(C{{l}_{2}}\) and HCl are 104 ,58 and 103 ...
The bond dissociation energies of gaseous H2, Cl2 and HCl are 104 ,58 and 103 kcal respectively. The enthalpy of formation of HCl gas would be,
(A) 44kcal
(B) 44kcal
(C) 22kcal
(D) 22kcal
Solution
Values of Bond energy are taken according to the balanced chemical equation of the reaction, also the coefficients of reactants and products are multiplied with the bond energy.
Complete step by step answer:
Bond energy is defined as the amount of energy required to break apart a mole of molecules into its component atoms. It is a measure of the strength of a chemical bond. Bond energy is also known as bond enthalpy or simply as bond strength.
The standard enthalpy of formation refers to the enthalpy change when one mole of a compound is formed from its elements. The standard enthalpy of formation, or standard heat of formation, of a compound is the change in enthalpy that accompanies the formation of one mole of the compound from its elements in their standard states.
21H2+21Cl2→HCl
Given bond energies of H2is 104kcal, Cl2is 58kcal , and HCl is 103 kcal.
According to the reaction, Enthalpy of formation HCl will be calculated using the bond energy of reactant and bond energy of product.
By the formula of enthalpy of formation, we get,