Question

The bond angles of $NH _{3}, NH _{1}^{+}$and $NH _{2}^{-}$are in the order

• A. $NH^{-}_2 > NH_3 > NH^+_4$
• B. $NH^+_4 > NH_3 > NH^{-}_2$
• C. $NH_3 > NH^{-}_2 > NH^+_4$
• D. $NH > NH^+_4 > NH^{-}_2$

Answer 1

Answer: (B)

$NH^+_4 > NH_3 > NH^{-}_2$

Answer 2

As the number of lone pairs of electrons increases, bond angle decreases. Thus, the order of bond angle is
$\underset{( no / p )}{NH _{4}^{+}} > \underset{(1 / p )}{NH _{3}} > \underset{(2 / p )}{NH _{2}^{-}}$