Question

The bond angle in $\text{As}{{\text{H}}_{\text{3}}}$ is greater than that in:

• A. $N{{H}_{3}}$
• B. ${{H}_{2}}O$
• C. $BC{{l}_{3}}$
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

$\text{BC}{{\text{l}}_{\text{3}}}$ has bond angle equal to $\text{12}{{\text{0}}^{o}}$ (trigonal planar). $\text{N}{{\text{H}}_{\text{3}}}$ and ${{\text{H}}_{\text{2}}}\text{O}$ have $\text{s}{{\text{p}}^{3}}$ hybridization but due to the presence of lone pair of electrons, they have bond angle less than 1 ${{109}^{o}}28$ $(N{{H}_{3}}-{{107}^{o}},{{H}_{2}}O-{{104.5}^{o}}),$ $\text{As}{{\text{H}}_{\text{3}}}$ ( $s{{p}^{3}}$ hybrid) has smaller bond angle than $\text{N}{{\text{H}}_{\text{3}}}$ due to less electronegativity of As than N.