The Bohr radius of an atom of nuclear charge Z is of order –... | PHYSICS - DE BROGLIE'S EXPLANATION OF BOHR'S SECOND POSTULATE OF QUANTISATION | SolveeIt

Question

The Bohr radius of an atom of nuclear charge Z is of order –

$\frac{\hslash}{Z\alpha mc}$

$\frac{Z\alpha\hslash}{mc}$

$\frac{mc}{Z\alpha\hslash}$

$\frac{m\alpha}{Zc\hslash}$

Answer

$\frac{\hslash}{Z\alpha mc}$

Explanation

Solution

The Bohr radius for a hydrogen-like atom of nuclear charge Z and one electron outside complete shells is $\frac{\hslash}{me^{2}Z}$ = $\frac{\hslash}{Z\alpha mc}$ . Thus the correct answer is (1)

Question: The Bohr radius of an atom of nuclear charge Z is of order –...

Solution