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Question

Physics Question on Oscillations

The bob of a simple pendulum executes simple harmonic motion in water with a period tt, while the period of oscillation of the bob is t0t_0 in air. Neglecting frictional force of water and given that the density of the bob is (43)×1000kg/m3.\left(\frac{4}{3}\right)\times1000\,kg/m^{3}. What relationship between tt and t0t_0 is true?

A

t=t0t = t_0

B

t=t0/2t = t_0/2

C

t=2t0t = 2t_0

D

t=4t0t = 4t_0

Answer

t=2t0t = 2t_0

Explanation

Solution

TT0=1(1ρρ)=1113\frac{T}{T_{0}} = \sqrt{\frac{1}{\left(1-\frac{\rho'}{\rho}\right)}} = \sqrt{\frac{1}{1-\frac{1}{3}}} TT0=2\Rightarrow \frac{T}{T_{0}} = 2 or, T=2T0T = 2T_{0}