Solveeit Logo

Question

Question: The block of mass M moving on the frictionless horizontal surface collides with a spring of spring c...

The block of mass M moving on the frictionless horizontal surface collides with a spring of spring constant K and compresses it by L. The maximum momentum of the block after collision is

A

MK\sqrt{MK}L

B

KL22M\frac{KL^{2}}{2M}

C

Zero

D

ML2K\frac{ML^{2}}{K}

Answer

MK\sqrt{MK}L

Explanation

Solution

12KL2=p22Morp=MKL\frac{1}{2}KL^{2} = \frac{p^{2}}{2M}orp = \sqrt{MK}L