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Question: The blades of a windmill sweep out a circle of area A. If the wind flows at a velocity v perpendicul...

The blades of a windmill sweep out a circle of area A. If the wind flows at a velocity v perpendicular to the circle, then the mass of the air of density ρ\rho passing through it in time t is :

A
B
C

Av2ρtA v ^ { 2 } \rho t

D

12Avρt\frac { 1 } { 2 } \mathrm { Av \rho t }

Answer
Explanation

Solution

Volume of wind flowing per second = Av

Mass of wind flowing per second =

Mass of air passing in time t s =