Question

The bisectors BD and CF of a triangle ABC have equations

y = x and x = 10. If A is (3, 5) then equation of BC is-

• A. 5y –2x = 11
• B. 6y –5x = 17
• C. 6y –x = 13
• D. None of these

Answer 1

Answer: (C)

6y –x = 13

Answer 2

Clearly reflection of A on y = x and x = 10 should lie on the

line BC

So, (5, 3) and (17, 5) should lies on BC

\ Equation of BC is Ž y – 3 = $\frac{5 - 3}{17 - 5}$ (x –5)

Ž 6y – x = 13