Question

The bisectors BD and CF of a triangle ABC have equations

y = x and x = 10. If A is (3, 5) then equation of BC is –

• A. 5y – 2x = 11
• B. 6y – 5x = 17
• C. 6y – x = 13
• D. None of these

Answer 1

Answer: (C)

6y – x = 13

Answer 2

Clearly, reflection of A on y =x and x = 10 should lie on the line BC.

So, (5, 3) & (17, 5) should lies on BC

\ Equation of BC is

Ž y–3=$\frac { 5 - 3 } { 17 - 5 }$(x–5)

Ž 6y – x = 13