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Question: The binomial coefficient of middle term in the expansion of $\left(\frac{2}{x}-\frac{x}{2}\right)^9$...

The binomial coefficient of middle term in the expansion of (2xx2)9\left(\frac{2}{x}-\frac{x}{2}\right)^9, can be

A

108

B

126

C

132

D

164

Answer

126

Explanation

Solution

The expansion of (2xx2)9\left(\frac{2}{x}-\frac{x}{2}\right)^9 has n+1=10n+1=10 terms. For an even number of terms, there are two middle terms: the 5th and 6th. The general term is Tr+1=(nr)anrbrT_{r+1} = \binom{n}{r} a^{n-r} b^r. For the 5th term, r=4r=4, giving coefficient (94)\binom{9}{4}. For the 6th term, r=5r=5, giving coefficient (95)\binom{9}{5}. Since (94)=(95)\binom{9}{4} = \binom{9}{5}, the binomial coefficient is unique. Calculating (94)=9×8×7×64×3×2×1=126\binom{9}{4} = \frac{9 \times 8 \times 7 \times 6}{4 \times 3 \times 2 \times 1} = 126.