Question: The binding energy per nucleon of deuteron $(_{1}^{2}H)$ and helium nucleus $(_{2}^{4}He)$ is 1....

Question

The binding energy per nucleon of deuteron $(_{1}^{2}H)$ and helium nucleus $(_{2}^{4}He)$ is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

Answer 1

Solution

$1H^{2} +_{1}H^{2} \rightarrow_{2}He^{4} + Q$

Total binding energy of helium nucleus = 4 × 7 = 28 MeV

Total binding energy of each deutron = 2 × 1.1 = 2.2 MeV

Hence energy released = 28 – 2 × 2.2 = 23.6 MeV

Question: The binding energy per nucleon of deuteron \((_{1}^{2}H)\) and helium nucleus \((_{2}^{4}He)\) is 1....

Solution